Get URL info (file size, Content-Type, etc.)
Problem
You have a URL and you want to get some info about it. For instance, you want to figure out the content type (text/html, image/jpeg, etc.) of the URL, or the file size without actually downloading the given page.
Solution
Let’s see an example with an image. Consider the URL http://www.geos.ed.ac.uk/homes/s0094539/remarkable_forest.preview.jpg .
#!/usr/bin/env python import urllib def get_url_info(url): d = urllib.urlopen(url) return d.info() url = 'http://'+'www'+'.geos.ed.ac.uk'+'/homes/s0094539/remarkable_forest.preview.jpg' print get_url_info(url)
Output:
Date: Mon, 18 Oct 2010 18:58:07 GMT
Server: Apache/2.0.63 (Unix) mod_ssl/2.0.63 OpenSSL/0.9.8e-fips-rhel5 DAV/2 mod_fastcgi/2.4.6
X-Powered-By: Zope (www.zope.org), Python (www.python.org)
Last-Modified: Thu, 08 Nov 2007 09:56:19 GMT
Content-Length: 103984
Accept-Ranges: bytes
Connection: close
Content-Type: image/jpeg
That is, the size of the image is 103,984 bytes and its content type is indeed image/jpeg.
In the code d.info()
is a dictionary, so the extraction of a specific field is very easy:
#!/usr/bin/env python import urllib def get_content_type(url): d = urllib.urlopen(url) return d.info()['Content-Type'] url = 'http://'+'www'+'.geos.ed.ac.uk'+'/homes/s0094539/remarkable_forest.preview.jpg' print get_content_type(url) # image/jpeg
This post is based on this thread.
Update (20121202)
With requests:
>>> import requests >>> from pprint import pprint >>> url = 'http://www.geos.ed.ac.uk/homes/s0094539/remarkable_forest.preview.jpg' >>> r = requests.head(url) >>> pprint(r.headers) {'accept-ranges': 'none', 'connection': 'close', 'content-length': '103984', 'content-type': 'image/jpeg', 'date': 'Sun, 02 Dec 2012 21:05:57 GMT', 'etag': 'ts94515779.19', 'last-modified': 'Thu, 08 Nov 2007 09:56:19 GMT', 'server': 'Apache/2.0.63 (Unix) mod_ssl/2.0.63 OpenSSL/0.9.8e-fips-rhel5 DAV/2 mod_fastcgi/2.4.6', 'x-powered-by': 'Zope (www.zope.org), Python (www.python.org)'}
so how to extract the [‘content-length’] form pprint(r.headers)
i tried pprint(r.headers)[‘content-length’]
not working , getting error
print(r.headers['content-length'])